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9x^2+729x=0
a = 9; b = 729; c = 0;
Δ = b2-4ac
Δ = 7292-4·9·0
Δ = 531441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{531441}=729$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(729)-729}{2*9}=\frac{-1458}{18} =-81 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(729)+729}{2*9}=\frac{0}{18} =0 $
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